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-2.6x^2+7.6x=1.2
We move all terms to the left:
-2.6x^2+7.6x-(1.2)=0
We add all the numbers together, and all the variables
-2.6x^2+7.6x-1.2=0
a = -2.6; b = 7.6; c = -1.2;
Δ = b2-4ac
Δ = 7.62-4·(-2.6)·(-1.2)
Δ = 45.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7.6)-\sqrt{45.28}}{2*-2.6}=\frac{-7.6-\sqrt{45.28}}{-5.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7.6)+\sqrt{45.28}}{2*-2.6}=\frac{-7.6+\sqrt{45.28}}{-5.2} $
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